Dr. Thomas Pacheco

Dr. Pacheco provides outstanding dental care to patients at our Total Health Dental Care Office on Broadway in Old Oakland. Dr. Pacheco focuses on prevention and uses nutrition as a tool to help patients overcome long-term dental issues such as gum disease, loss of teeth and cavities. He offers full general dental services as well as cosmetic services such as Invisalign aligners and implants. Dr. Pacheco has completed over 300 hours of continued education and is certified to administer oral conscious sedation for patients with dental anxiety. Dr. Pacheco grew up in Southern California but moved to Berkeley for his undergraduate studies. He was fortunate to have mentors early on that exposed him to the different sides of the dental profession. His decision to practice dentistry, however, was shaped by being able to help others every day. Dr. Pacheco loves combining that dedication to service with both the science and art of dentistry. After graduating from Cal, Dr. Pacheco attended dental school at the University of the Pacific's Arthur A. Dugoni School of Dentistry. While in dental school, he was a Tau Kappa Omega Dental honor student and won distinguishing dental scholarships, such as the Jim and Carolyn Pride Scholarship. As a board-certified dentist, Dr. Pacheco is a member of the Academy of General Dentistry, the California Dental Association, American Dental Association and the Alameda County Dental Society. Dr. Pacheco has practiced with Total Health Dental Care for many years and has a continued passion to learn the latest technologies and the newest techniques. He stays up-to-date with advancements in dentistry to expand his knowledge and skillset and better serve his patients. At the core of his philosophy, Dr. Pacheco strives to educate and empower his patients so they feel comfortable and confident in their smiles and overall health. When he’s not at Total Health, Dr. Pacheco hikes, reads, cooks with his wife and explores the Bay Area culinary scene. He recently did his first triathlon.